5x^2=270x

Solution for 5x^2=270x equation:

5x^2=270x

We move all terms to the left:

5x^2-(270x)=0

a = 5; b = -270; c = 0;
Δ = b2-4ac
Δ = -2702-4·5·0
Δ = 72900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{72900}=270$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-270)-270}{2*5}=\frac{0}{10}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-270)+270}{2*5}=\frac{540}{10}
=54
$